X

Number of individuals

Using example data:

ID	phenocode	age
FG1	EXAMPLE_ENDPOINT	45
FG1	ENDPOINT_XYZ	46
FG1	DEATH	47
FG2	EXAMPLE_ENDPOINT	30
FG2	EXAMPLE_ENDPOINT	30.1
FG3	ENDPOINT_XYZ	50

In this example the number of individuals is 2, since only 2 unique individuals (FG1 and FG2) have EXAMPLE_ENDPOINT events.

X

Unadjusted prevalence

Using example data:

ID	phenocode	age
FG1	EXAMPLE_ENDPOINT	45
FG1	ENDPOINT_XYZ	46
FG1	DEATH	47
FG2	EXAMPLE_ENDPOINT	30
FG2	EXAMPLE_ENDPOINT	30.1
FG3	ENDPOINT_XYZ	50

In this example the unadjusted prevalence is 66 %.

The unadjusted prevalence is the number of individuals having an endpoint divided by the total number of individuals.

Here:

• 2 unique individuals (FG1 and FG2) have EXAMPLE_ENDPOINT events
• 1 individual (FG3) has no EXAMPLE_ENDPOINT event

So the unadjusted prevalence is 2 / 3 = 66 %.

X

Mean age at first event

Using example data:

ID	phenocode	age
FG1	EXAMPLE_ENDPOINT	45
FG1	ENDPOINT_XYZ	46
FG1	DEATH	47
FG2	EXAMPLE_ENDPOINT	30
FG2	EXAMPLE_ENDPOINT	30.1
FG3	ENDPOINT_XYZ	50

In this example the mean age at first event is 37.5.

The mean age at first event for EXAMPLE_ENDPOINT is computed by:

• selecting individuals having EXAMPLE_ENDPOINT: FG1 and FG2
• for these individuals, taking the age of their first event of EXAMPLE_ENDPOINT: 45 for FG1 and 30 for FG2
• computing the mean of these values

So the mean age at first event is Mean(45, 30) = 37.5.

X

Case fatality at 5 years

Using example data:

ID	phenocode	age
FG1	EXAMPLE_ENDPOINT	45
FG1	ENDPOINT_XYZ	46
FG1	DEATH	47
FG2	EXAMPLE_ENDPOINT	30
FG2	EXAMPLE_ENDPOINT	30.1
FG3	ENDPOINT_XYZ	50

In this example the case fatality at 5 years is 50%.

The case fatality at 5 years is computed by:

• selecting individuals with EXAMPLE_ENDPOINT events:
  FG1 and FG2.
• for each of them, checking if they have a DEATH event:
  FG1 has this event.
• checking the number of individuals for which 5 years or less happened between the first event of EXAMPLE_ENDPOINT and the DEATH event:
  only 1 (FG1, with 47 - 25 = 2 years between said events).

Here only 1 individual has less than 5 years between EXAMPLE_ENDPOINT and DEATH, and 2 individuals have EXAMPLE_ENDPOINT. The case fatality at 5 years is 1 / 2 = 50 %.

X

Median number of events per individual

Using example data:

ID	phenocode	age
FG1	EXAMPLE_ENDPOINT	45
FG1	ENDPOINT_XYZ	46
FG1	DEATH	47
FG2	EXAMPLE_ENDPOINT	30
FG2	EXAMPLE_ENDPOINT	30.1
FG3	ENDPOINT_XYZ	50

In this example the median number of events is 1.5.

The median number of events is computed by:

• selecting individuals with EXAMPLE_ENDPOINT:
  FG1, FG2
• counting the number of EXAMPLE_ENDPOINT events for each of these individuals:
  • 1 event for FG1
  • 2 events for FG2
• computing the median of these values.

Here the median number of events per individual is Median(1, 2) = 1.5.

X

Recurrence within 6 months

Using example data:

ID	phenocode	age
FG1	EXAMPLE_ENDPOINT	45
FG1	ENDPOINT_XYZ	46
FG1	DEATH	47
FG2	EXAMPLE_ENDPOINT	30
FG2	EXAMPLE_ENDPOINT	30.1
FG3	ENDPOINT_XYZ	50

In this example the recurrence within 6 months is 50 %.

The recurrence within 6 months is computed by:

• selecting individuals with EXAMPLE_ENDPOINT:
  FG1, FG2, so 2 individuals in total.
• for each of them, checking if they have 2 events of EXAMPLE_ENDPOINT less than 6 months apart:
  • FG1 has only 1 event of EXAMPLE_ENDPOINT so FG1 is discarded.
  • FG2 has 2 events of EXAMPLE_ENDPOINT less than 6 months apart (one at age 30 and the other at age 30.1).
• counting the number of individuals with events less than 6 months apart:
  1 in this case (FG2)

Here the recurrence within 6 months is 1 / 2 = 50 %.